Asked by popy
For what values of s will the limit of x approach infininty for lnx/x^s.
Answers
Answered by
drwls
Your question is unclear. Do you want the limit of lnx/x^s AS x-> infinity to be finite? or infinite?
I suggest you use L'Hopital's rule to compute the limit. That involves takng the ratio of the derivatives of the numerator and the denominator, which is (1/x)/[sx^(s-1)]= (1/s)[x^-s)]
That limit will be zero if s>0 and infinite if s<0.
I suggest you use L'Hopital's rule to compute the limit. That involves takng the ratio of the derivatives of the numerator and the denominator, which is (1/x)/[sx^(s-1)]= (1/s)[x^-s)]
That limit will be zero if s>0 and infinite if s<0.
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