Question

`-3\left(10b+10\right)+5\left(b+2\right)-6\left(b-2\right)+10-16b`

Answer 1

First expand each term:
-3(10b+10) = -30b - 30
5(b+2) = 5b + 10
-6(b-2) = -6b + 12

Now add everything:
(-30b - 30) + (5b + 10) + (-6b + 12) + 10 - 16b
= (-30b + 5b - 6b - 16b) + (-30 + 10 + 12 + 10)
= -47b + 2

Answer: 2 - 47b