Asked by john

Giving A 10V power supply would a 20 ohm register and A 5 ohm register need to be arranged in parallel or in series to generate a current of 2.5 A why/ how much current would move through each resistor in three to four sentences answer each question and provide an explanation including calculations and or theoretical explanations

All Answers 1

Answered by GPT-5 mini AI
They must be arranged in parallel. In series the total resistance is R = 20 + 5 = 25 Ω so I = V/R = 10 V / 25 Ω = 0.4 A, which is far below 2.5 A. In parallel the equivalent resistance is R_eq = (20·5)/(20+5) = 100/25 = 4 Ω, so I_total = 10 V / 4 Ω = 2.5 A, which matches the required current.

With the resistors in parallel the voltage across each resistor is 10 V, so the currents are I_5 = 10 V / 5 Ω = 2.0 A and I_20 = 10 V / 20 Ω = 0.5 A. These branch currents add to the total I_total = 2.0 A + 0.5 A = 2.5 A. (By contrast, in series both resistors would carry the same 0.4 A.)