Question

Which table represents viable solutions for y = 5x, where x is the number of tickets sold for the school play and y is the amount of money collected for the tickets?

A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 100, negative 25, 40, 600. The second column is labeled money collected (y) with entries negative 500, negative 125, 250, 3000.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 20, 20, 100, 109. The second column is labeled money collected (y) with entries negative 100, 100, 500, 545.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 0, 10, 51, 400. The second column is labeled money collected (y) with entries 0, 50, 255, 2000.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 5, 65, 80, 200. The second column is labeled money collected (y) with entries 25, 350, 400, 1000.

Answer 1

The third table (x = 0, 10, 51, 400 with y = 0, 50, 255, 2000).

Reason: y must equal 5x and x (tickets) can't be negative. In that table 5·0=0, 5·10=50, 5·51=255, 5·400=2000, and all x are nonnegative.