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An electron travels at a speed of 4.0×104 m/s through a uniform magnetic field whose magnitude is 1.4×10−3 T. What is the magni...Asked by Lisa
An electron travels at a speed of 1.0×104 through a uniform magnetic field whose magnitude is 1.2×10−3 . What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are perpendicular?
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Answered by
Rony
F = MA
F = qv*B
ma = qvb
a = qbv/m
m = mass of electron
q = charge of electron
F = qv*B
ma = qvb
a = qbv/m
m = mass of electron
q = charge of electron
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