Question
a helicopter of mass m has an acceleration of magnitude 0.12 upward. a)determine the force required to cause this aaceleration?
b) how much work is done by this force in moving the helicopter a distance deltay upward?
b) how much work is done by this force in moving the helicopter a distance deltay upward?
Answers
A.
Fnet=ma
Fx-Fg=ma
Fx=ma+Fg
Fx=m(0.12g)+mg
Fx=0.12mg+mg
Fx=1.12mg
B.
W=(Fx) (deltaY)
=1.12mg(delta)Y
Fnet=ma
Fx-Fg=ma
Fx=ma+Fg
Fx=m(0.12g)+mg
Fx=0.12mg+mg
Fx=1.12mg
B.
W=(Fx) (deltaY)
=1.12mg(delta)Y
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