A 19.5-g sample of a metal was heated to 61.67°C. When the metal was placed into 26.5 g of water in a calorimeter, the temperature of the water increased from 25.00°C to 30.00°C. What is the specific heat of the metal?

Answer 1

heat lost by metal + heat gained by H2O=0.

[mass metal x specific heat metal (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for specific heat metal, the only unknown..