105 of is initially at room temperature (22). A chilled steel rod at 2 is placed in the water. If the final temperature of the system is 21.3, what is the mass of the steel bar?

Question

Specific heat of water = 4.18

Specific heat of steel = 0.452

Answer 1

without units, numbers are just plain meaningless.

Answer 2

105 ml of H20 is initially at room temperature (22 C). A chilled steel rod at 2C is placed in the water. If the final temperature of the system is 21.3C, what is the mass of the steel bar?

Specific heat of water = 4.18 J/g*C

Specific heat of steel = 0.452 J/g*C

Answer 3

32

Answer 4

120 of is initially at room temperature (22). A chilled steel rod at 2 is placed in the water. If the final temperature of the system is 21.0, what is the mass of the steel bar?
Specific heat of water = 4.18

Specific heat of steel = 0.452

Answer 5

'lmk

Answer 6

48.4 grams