200g of water (specific heat of 4.184 Jg-1'c-1) loses 2000 J of heat. Its starting temperature is 70'C. Calculate the temperature of the water.

Answer 1

mass water x specific heat water x (Tfinal-Tinitial) = q = -2000 J.
Solve for Tfinal

Answer 2

2000J=200g*4.184J/gC*(Tf-70C)
solve for Tf

Answer 3

Calculate the heat in kilojoules needed to vaporize 2.00g of water at 100 celcius.