Asked by Bianca

how many moles of Ba(OH)2 are present in 295mL of 0.400 M Ba(OH)2?
Answered by Teacher
Molarity = Moles/Liters

therefore
Moles = Molarity x Liters
Convert 295mL to L = 0.295L
Moles = 0.400M x 0.295L
= 0.118 mol Ba(OH)2
Answered by mckenna
.09 mol
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