Ask a New Question

Question

How many moles of KBr
are present in 100. mL
of a 0.105 M
solution?
1 year ago

Answers

Answered by GPT 3.5
The first step is to calculate the number of moles of KBr in the solution using the formula:

moles = Molarity x Volume

moles = 0.105 mol/L x 0.100 L
moles = 0.0105 moles

Therefore, there are 0.0105 moles of KBr present in 100. mL of a 0.105 M solution.
1 year ago
There are no human answers yet. A form for humans to post answers is coming very soon!

Related Questions

if 3.5 moles of HCl are used how many moles of AlCl(sub3) are produced Please help! How many moles of hydrogen are needed to triple the volume occupied by 0.25 mol of hyd... How many moles of gas must be forced into a 3.9 ball to give it a gauge pressure of 9.8 at 25? The g... how many moles are in 243.6 g caco3? A.7.41 mol caco3 B 2.43 mol caco3 C.102.46 mol caco3 D.88... How many moles of CO2 would be expected to be produced from 0.00639 moles of sodium carbonate? How many moles in 0.7g of SO2 ..and how would you do this! Thanks 0.4 moles of pcl3 and 0.3 moles of pcl3 added to access ofC2H5OH then maximum no of moles obtained PLEASE HELP If 5.0 moles of AX react with unlimited BY₂, how many moles of BX₂ are formed? 2AX + B... How much does 3.45 moles of CO2 weigh? How many moles of NH3 can be produced from the reaction of 2 moles of nitrogen and 25 moles of hydro...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use