Asked by anonymous
why does ln(1/x)= -1/x ?
Answers
Answered by
jai
is that the derivative? if it is,
ln(1/x) can be written as:
ln (x^-1) = -ln(x)
since the derivative of ln (x) is 1/x, then
derivative of -ln(x) = ln(1/x)= -1/x
hope this helps.
ln(1/x) can be written as:
ln (x^-1) = -ln(x)
since the derivative of ln (x) is 1/x, then
derivative of -ln(x) = ln(1/x)= -1/x
hope this helps.
Answered by
anonymous
ohhh~ Thank You!
Answered by
Bosnian
ln(1/x)= ln(1)-ln(x)
ln(1))=0
ln(1)-ln(x)=0-ln(x)= -ln(x)
ln(1/x)=-ln(x)
ln(1))=0
ln(1)-ln(x)=0-ln(x)= -ln(x)
ln(1/x)=-ln(x)
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