Asked by saad
x2-x-1806=0 by completing the square
Answers
Answered by
bobpursley
x^2-x+1/4=1806+1/4
(x-1/2)^2=( ? ) squared.
x-1/2= +- sqrt (1806+1/4)
(x-1/2)^2=( ? ) squared.
x-1/2= +- sqrt (1806+1/4)
Answered by
khurram
x^2-x-1806=0
x^2-x=1806
x^2-x+(1/2)^2=1806+(1/2)^2
(x-1/2)^2=1806+1/4
(x-1/2)^2=7224+1/4
(x-1/2)^2=7225/4
as going
x^2-x=1806
x^2-x+(1/2)^2=1806+(1/2)^2
(x-1/2)^2=1806+1/4
(x-1/2)^2=7224+1/4
(x-1/2)^2=7225/4
as going
Answered by
Mahnoor
Agyee ka solution nai hay na upper walay question may
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