How much power is needed to push a box (mass 27 kg) over a surface (coefficient of friction μk=0.5) with a velocity of 1.1 m/s?

Answer 1

force = uk * m * g = 0.5*27*9.81 Newtons

Power = force*speed in direction of force
= .5*27*9.81*1.1 Watts

Answer 2

watts wouldn't be the units correct. My answer is 1456.785

Answer 3

Joules per second is watts
I get 145.67 Watts

Answer 4

Okay I got it thanks for the help.