Asked by molly
How much power is needed to push a box (mass 27 kg) over a surface (coefficient of friction μk=0.5) with a velocity of 1.1 m/s?
Answers
Answered by
Damon
force = uk * m * g = 0.5*27*9.81 Newtons
Power = force*speed in direction of force
= .5*27*9.81*1.1 Watts
Power = force*speed in direction of force
= .5*27*9.81*1.1 Watts
Answered by
molly
watts wouldn't be the units correct. My answer is 1456.785
Answered by
Damon
Joules per second is watts
I get 145.67 Watts
I get 145.67 Watts
Answered by
molly
Okay I got it thanks for the help.
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