Asked by Rose
Calculate the power needed from the motor of an elevator for it to be able to lift a 1x10^4kg mass a distance of 20m in 5s. (Enter your answer in scientific notation utilizing "e" format and rounding the decimal value to one decimal place.)
I used the equation p = w/t
1e4kg(20m)/5s = 40,000J --> 4.0e4
My answer was incorrect. Please help!
I used the equation p = w/t
1e4kg(20m)/5s = 40,000J --> 4.0e4
My answer was incorrect. Please help!
Answers
Answered by
Henry
F = m*g = 1*10^4kg * 9.8N/kg = 9.8*10^4N
P = F*d/t = 9.8*10^4 * 20/5 = 3.92*10^5
J/s = 3.92*10^5 Watts. = 3.92e5 Watts.
Note: Your Eq should have been m*g * d/t
You omitted g(9.8m/s^2).
P = F*d/t = 9.8*10^4 * 20/5 = 3.92*10^5
J/s = 3.92*10^5 Watts. = 3.92e5 Watts.
Note: Your Eq should have been m*g * d/t
You omitted g(9.8m/s^2).
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