Asked by Anonymous
f(x)= (x^2-1)^3,is its derivative f'(x)= 6x^5 -12x^3 + 6x.
Is there an alternative answer, because a computer generated answer is diff then mine. please help.
Is there an alternative answer, because a computer generated answer is diff then mine. please help.
Answers
Answered by
jai
yes, that's the derivative.
did you expand your answer? or how did you do it?
did you expand your answer? or how did you do it?
Answered by
Anonymous
I used the chain rule... my working is above
y = u^3 where u= (x^2-1)
so dy/du = 3u^2
and du/dx = 2x
then dy/dx = 3u^2(2x)
so after that substitute u
3(x^2-1)^2(2x)
=6x(x^2-1)^2
and I expanded it and got
6x^5-12x^3+6x
is that correct?
because a computer generated answer says you can simplify (x^2-1) since it is a perfect square and they get a diff answer than mine? However i cannot understand their simplification.
y = u^3 where u= (x^2-1)
so dy/du = 3u^2
and du/dx = 2x
then dy/dx = 3u^2(2x)
so after that substitute u
3(x^2-1)^2(2x)
=6x(x^2-1)^2
and I expanded it and got
6x^5-12x^3+6x
is that correct?
because a computer generated answer says you can simplify (x^2-1) since it is a perfect square and they get a diff answer than mine? However i cannot understand their simplification.
Answered by
jai
yes, your answer is correct. :)
i think that simplification means to factor 6x(x^2-1)^2 into 6x[(x-1)^2][(x+1)^2]
i think that simplification means to factor 6x(x^2-1)^2 into 6x[(x-1)^2][(x+1)^2]
Answered by
Anonymous
I majorly confused here, I am using a computer software which gives me a different answer and i am doubting my work over an over again, the computer software tells me:
"squaring the expression means multiplying the expression by itself"
and then they expand 6x[(x-1)(x-1)][x+1]^2
and in the next step then suddenly (x-1) is canceled and they just consider (x+1)(x+1)
Can someone explain me why the software does that, or is it just one of their ways to trick its users?
"squaring the expression means multiplying the expression by itself"
and then they expand 6x[(x-1)(x-1)][x+1]^2
and in the next step then suddenly (x-1) is canceled and they just consider (x+1)(x+1)
Can someone explain me why the software does that, or is it just one of their ways to trick its users?