Asked by Anonymous
                How would one take the derivative of "f(x)^[g(x)]? Is there a formula I can follow to differentiate functions like that?
            
            
        Answers
                    Answered by
            Reiny
            
    you will have to take the natural log of both sides.
I will illustrate with an example
e.g.
y = (x^2+1)^(2x+3)
ln y = ln ((x^2+1)^(2x+3))
ln y = (2x+3)(ln(x^2+1)
now differentiate, using the product rule on the right side.
(dy/dx)/y = (2x+3)(2x/(x^2+1)) + 2ln(x^2+1)
dy/dx = y((2x+3)(2x/(x^2+1)) + 2ln(x^2+1))
you could then replace y with its original value and simplify, but that would be a general method.
    
I will illustrate with an example
e.g.
y = (x^2+1)^(2x+3)
ln y = ln ((x^2+1)^(2x+3))
ln y = (2x+3)(ln(x^2+1)
now differentiate, using the product rule on the right side.
(dy/dx)/y = (2x+3)(2x/(x^2+1)) + 2ln(x^2+1)
dy/dx = y((2x+3)(2x/(x^2+1)) + 2ln(x^2+1))
you could then replace y with its original value and simplify, but that would be a general method.
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