Question

can someone help explain how to do this?
allen has nickels dimes and quarters in his pocket. the number of nickels is 1 more than twice the number of quarters. the number of dimes is 1 less than the number of quarters. if the value of change in his pocket is 85 cents, how many of each coin does he have?
number of quarters = x
number of nickels = 2x+1
number of dimes = x-1

now use the "value" of those coins to get
25x + 5(2x+1) + 10(x-1) = 85

should be pretty easy to solve

Related Questions

How do I figure out this problem? You have 37 coins (all nickels , dimes, and quarters) adding up to... Please help....struggling with word problems and please explain how to get the answer.... Max has... A city park employee collected 600 cents in nickels, dimes and quarters at the bottom of a wishing w... Tim has more pennies than nickels, more nickels than dimes, more dimes than quarters, and more quart...