Asked by Robbie
can someone help explain how to do this?
allen has nickels dimes and quarters in his pocket. the number of nickels is 1 more than twice the number of quarters. the number of dimes is 1 less than the number of quarters. if the value of change in his pocket is 85 cents, how many of each coin does he have?
allen has nickels dimes and quarters in his pocket. the number of nickels is 1 more than twice the number of quarters. the number of dimes is 1 less than the number of quarters. if the value of change in his pocket is 85 cents, how many of each coin does he have?
Answers
Answered by
Reiny
number of quarters = x
number of nickels = 2x+1
number of dimes = x-1
now use the "value" of those coins to get
25x + 5(2x+1) + 10(x-1) = 85
should be pretty easy to solve
number of nickels = 2x+1
number of dimes = x-1
now use the "value" of those coins to get
25x + 5(2x+1) + 10(x-1) = 85
should be pretty easy to solve
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.