Question

A 6-column table with 2 rows. The first column labeled number of washers has entries 1, 2. The second column labeled initial velocity v subscript 1 (meters per second) has entries 0.11, 0.13. The third column labeled final velocity v subscript 2 (meters per second) has entries 0.28, 0.36. The fourth column labeled time to travel 0.25 meters t subscript 1 (seconds) has entries 2.23, 1.96. The fifth column labeled time to travel 0.5 meters t subscript 2 (seconds) has entries 3.13, 2.61. The sixth column labeled Acceleration a = StartFraction (v subscript 2 minus v subscript 1) over (t subscript 2 minus t subscript 1) EndFraction (meters per second squared) has entries 0.19 and empty.
The acceleration of the car with two washers added to the string would be
.

Answer 1

Use a = (v2 − v1)/(t2 − t1).

a = (0.36 − 0.13)/(2.61 − 1.96) = 0.23/0.65 = 0.3538 m/s² ≈ 0.35 m/s².

So the acceleration with two washers is about 0.35 m/s².