To determine the net ionic equations for the given reactions, we need to identify the ions involved and determine the products formed. Let's break down each reaction step by step:
1. Potassium Fluoride (KF) and Ammonium Chloride (NH4Cl):
The chemical equation for this reaction is:
KF + NH4Cl → ?
Step 1: Write the dissociation equations for the compounds:
KF → K+ + F-
NH4Cl → NH4+ + Cl-
Step 2: Identify the exchange of ions:
K+ from KF combines with Cl- from NH4Cl to form KCl.
F- from KF combines with NH4+ from NH4Cl to form NH4F.
Step 3: Write the net ionic equation by removing the spectator ions:
The spectator ions are K+ and Cl-. They are present on both sides of the equation, so they can be ignored.
The net ionic equation for the reaction is:
F- + NH4+ → NH4F
2. Sodium Hydrogen Sulfite (NaHSO3) and Potassium Cyanide (KCN):
The chemical equation for this reaction is:
NaHSO3 + KCN → ?
Step 1: Write the dissociation equations for the compounds:
NaHSO3 → Na+ + HSO3-
KCN → K+ + CN-
Step 2: Identify the exchange of ions:
Na+ from NaHSO3 combines with CN- from KCN to form NaCN.
HSO3- from NaHSO3 combines with K+ from KCN to form KHSO3.
Step 3: Write the net ionic equation by removing the spectator ions:
The spectator ions are Na+ and HSO3-. They are present on both sides of the equation, so they can be ignored.
The net ionic equation for the reaction is:
CN- + K+ → KCN
By following these steps, we can determine the net ionic equations for these chemical reactions.