Asked by dan
I need to balance hydrolysis equations for the following salts,copper(II) nitrate, sodium tetraborate, sodium bromide, calcium sulfite, potassium sulfate,potassium chloride, sodium acetate, and ammonium bromide.
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Answered by
dan
Does this mean no one is able to or no one has had a chance to answer it?
Answered by
DrBob222
I'll try to get you started on two or three of these but no one here will do all of them for you.
NH4Br. The NH4^+ is hydrolyzed, the Br is not. (NH4Br is the salt of a weak base and a strong acid; therefore, the weak base part[i.e., the NH4] is hydrolyzed.
NH4^+ + H2O ==> NH3 + H3O^+
NaC2H3O2(sodium acetate) is the salt of a strong base and weak acid; therefore, the weak acid part (C2H3O2^-) is hydrolyzed but the strong base part (Na^+) is not.
C2H3O2^- + HOH ==> HC2H3O2 + OH^-
NaBr (sodium bromide) is the salt of a strong base (NaOH) and a strong acid (HBr); therefore, neither Na^+ nor Br^- is hydolyzed.
NH4Br. The NH4^+ is hydrolyzed, the Br is not. (NH4Br is the salt of a weak base and a strong acid; therefore, the weak base part[i.e., the NH4] is hydrolyzed.
NH4^+ + H2O ==> NH3 + H3O^+
NaC2H3O2(sodium acetate) is the salt of a strong base and weak acid; therefore, the weak acid part (C2H3O2^-) is hydrolyzed but the strong base part (Na^+) is not.
C2H3O2^- + HOH ==> HC2H3O2 + OH^-
NaBr (sodium bromide) is the salt of a strong base (NaOH) and a strong acid (HBr); therefore, neither Na^+ nor Br^- is hydolyzed.
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