Question
help please this question is driving my crazy.
Suppose there is a 2-degree drop in a temperature for every thousand feet that an
airplanes climbs into sky. If the temperature on the ground is 65 degrees, what would be
the temperature when the plane reaches an altitude of 23,000 ft?
Suppose there is a 2-degree drop in a temperature for every thousand feet that an
airplanes climbs into sky. If the temperature on the ground is 65 degrees, what would be
the temperature when the plane reaches an altitude of 23,000 ft?
Answers
23000/1000 = 23
23*2 = 46 degree-drop
therefore,
65-46 = 19 degrees
so there,, :)
23*2 = 46 degree-drop
therefore,
65-46 = 19 degrees
so there,, :)
after diving 90m below the sea level, a diver rises at a rate of 4 meters per minute for 8 min. Where is the diver in relation to the surface
distance = rate*time
distance = 4*8 = 32 meters
therefore,
90-32 = 58 meters BELOW sea level
so there,, :)
distance = 4*8 = 32 meters
therefore,
90-32 = 58 meters BELOW sea level
so there,, :)
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