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Asked by Kelly

The Ka values of H2CO3 are shown below.
Ka1 4.6 10-7
Ka2 4.4 10-11
What is the pH of a 0.17 M solution of Na2CO3?
14 years ago

Answers

Answered by DrBob222
Write the hydrolysis equation for carbonate ion.
CO3^-2 + HOH ==> HCO3^- + OH^-

Now set up an ICE chart and substitute into the Kb expression.
Kb = (Kw/k2) = (HCO3^-)(OH^-)/(CO3^-2)

(HCO3^-)= (OH^-) = x
(CO3^-2) = 0.17
You know Kw and k2.
Solve for x and convert to pH.
Post your work if you get stuck.
14 years ago

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