Asked by Anonymous
A finite geometric sequence has t1= 0.1024 and t2= 0.256 how many terms does this sequence have if its middle temr has the value 156.25?
how would go about and do this question?
If t<sub>1</sub> = 0.1024 and t<sub>2</sub> = 0.256, then the common ratio is t<sub>2</sub>/t<sub>1</sub> = 2.5
The value at term n is given by .1024 * 2.5 <sup>n-1</sup>, therefore solve
156.25 = .1024 * 2.5 <sup>n-1</sup> to find the middle term.
how would go about and do this question?
If t<sub>1</sub> = 0.1024 and t<sub>2</sub> = 0.256, then the common ratio is t<sub>2</sub>/t<sub>1</sub> = 2.5
The value at term n is given by .1024 * 2.5 <sup>n-1</sup>, therefore solve
156.25 = .1024 * 2.5 <sup>n-1</sup> to find the middle term.
Answers
Answered by
x2
guess and check on finding the middle term (it's 9) to get 18 terms
mathematically I thought you were supposed to log both sides
log156.25 = log(.1024*2.5)^n-1
log156.25 = n-1log(.256)<--power of log rule
log156.25/log(.256) =n-1
I did something wrong though... because my answer isn't right
mathematically I thought you were supposed to log both sides
log156.25 = log(.1024*2.5)^n-1
log156.25 = n-1log(.256)<--power of log rule
log156.25/log(.256) =n-1
I did something wrong though... because my answer isn't right
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