Asked by Aria
Geometric series: Finite and infinite
n=5
a1=243
r=2/3
i=1
This is the equation
243(2/3)^i
My answer is 633
n=infinity sign
a1=5
r=-1/4
i=1
The equation
5(-1/4)^i-1
I think its undefined
n=5
a1=243
r=2/3
i=1
This is the equation
243(2/3)^i
My answer is 633
n=infinity sign
a1=5
r=-1/4
i=1
The equation
5(-1/4)^i-1
I think its undefined
Answers
Answered by
Steve
a1=243
r = 2/3
an = 243(2/3)^(n-1)
a5 = 48
s = a/(1-r) = 5/(5/4) = 4
r = 2/3
an = 243(2/3)^(n-1)
a5 = 48
s = a/(1-r) = 5/(5/4) = 4