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Find all critical numbers:

2x*sqrt(3x^2+4)?
14 years ago

Answers

Reiny
is this
y = 2x*sqrt(3x^2+4) ?

critical number are
x and y intercepts, max/min points and points of inflection

for x-intercept, let y = 0
for y-intercept , let x = 0

for max/min , take first derivative, set equal to zero and solve for x. Sub back into original to get the matching y

for pts. of inflection, set second derivative to zero and solve for x
sub back into original to get the y

use product rule to find first derivative.
14 years ago

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