Asked by Anonymous

A passenger in a helicopter traveling upwards at 27 m/s accidentally drops a package out the window. If it takes 17 seconds to reach the ground, how high to the nearest meter was the helicopter when the package was dropped?

Answers

Answered by Henry
d = Vo*t + 0.5*9.8t^2,
d = -27*17 + 0.5*9.8(17)^2,
= -459 + 1416 = 957 m.

The neg. initial velocity means the helicopter is moving in opposite direction of the free falling object.

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