Question
Q10. Sitting in the passenger seat you observe that the drive of the car needs only 3 seconds to come from a speed of 35 mph on the entrance ramp to the interstate to a speed of 70 mph on the interstate. What is the car's acceleration? How much distance does the car cover during those 3 seconds?
Answers
oobleck
(70-35)/3 = ___ mi/hr-s
s = vt + 1/2 at^2
s = 35/3600 mi/s * 3s + 1/2 (35/(3*3600)) mi/s^2 * (33 s)^2 = 7/160 mi
s = vt + 1/2 at^2
s = 35/3600 mi/s * 3s + 1/2 (35/(3*3600)) mi/s^2 * (33 s)^2 = 7/160 mi