Asked by Claire
Ready Mix Concrete Company is planning on developing new markets in a growing community. It had recently acquired large orders in three locations: downtown, at a mall, and in a suburb. The destinations and loads to be delivered are the following:
Delivery Site:
Downtown
Location Coordinate (X,Y): (20, 10)
Loads to site: 22
Cost of load per mile: $10
Mall
Location Coordinate (X,Y): (10, 40)
Loads to site: 43
Cost of load per mile: $10
Suburb
Location Coordinate (X,Y): (40, 20)
Loads to site: 36
Cost of load per mile: $10
Develop a marketing plan for evolving these three markets.
I'm confused on what I'm supposed to do so I need help.
All I've done so far is create a location analysis graph and found the distances between each place:
Using d= Squareroot of (X2-X1)squared+(Y2-Y1)squared
Mall to Suburb: 36
Mall to Downtown 32
Downtown to Suburb = 22
Delivery Site:
Downtown
Location Coordinate (X,Y): (20, 10)
Loads to site: 22
Cost of load per mile: $10
Mall
Location Coordinate (X,Y): (10, 40)
Loads to site: 43
Cost of load per mile: $10
Suburb
Location Coordinate (X,Y): (40, 20)
Loads to site: 36
Cost of load per mile: $10
Develop a marketing plan for evolving these three markets.
I'm confused on what I'm supposed to do so I need help.
All I've done so far is create a location analysis graph and found the distances between each place:
Using d= Squareroot of (X2-X1)squared+(Y2-Y1)squared
Mall to Suburb: 36
Mall to Downtown 32
Downtown to Suburb = 22
Answers
Answered by
bobpursley
"Develop a marketing plan for evolving these three markets"
You are correct, the world wonders what this means.
I think I would look for a location that minimizes transportation costs, and assume that this can be used for staging concrete to be transported to the sites. Concrete doesn't work that way, but otherwise, I have no idea.
YOu have three sites: (20,10),(10,40),and (40,20). These have to be weighed to amount of loads, and not cost, since all are the same per mile.
X X*loads
20...440
10...430
40...1440
weighted average= (440+430+1440)/loadstotal
X avg= 2310/101=23
do the same for y, then that x,y location is the min cost place for a warehouse/storage site.
You are correct, the world wonders what this means.
I think I would look for a location that minimizes transportation costs, and assume that this can be used for staging concrete to be transported to the sites. Concrete doesn't work that way, but otherwise, I have no idea.
YOu have three sites: (20,10),(10,40),and (40,20). These have to be weighed to amount of loads, and not cost, since all are the same per mile.
X X*loads
20...440
10...430
40...1440
weighted average= (440+430+1440)/loadstotal
X avg= 2310/101=23
do the same for y, then that x,y location is the min cost place for a warehouse/storage site.
Answered by
Claire
ok I did that and got x as 23 and y as 26 so when i use that against the three sites why are they not the same distance?
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