Asked by Lulu
In a titration, 3.4 g of an acid (HX) requires 21.5 mL of 0.85 M NaOH(aq) for complete reaction. What is the molar mass of the acid? Answer in units of g/mol. im not really sure how to even start... but i calculated the moles of NaOH which i got to be .018 moles.... what do i do from here?
Answers
Answered by
DrBob222
HX + NaOH ==> NaX + H2O
moles NaOH = M x L = ??
moles HX must be the same since the reaction is 1:1.
moles HX = grams/molar mass.
You know moles HC and grams HX, solve for molar mass HX.
moles NaOH = M x L = ??
moles HX must be the same since the reaction is 1:1.
moles HX = grams/molar mass.
You know moles HC and grams HX, solve for molar mass HX.
Answered by
Lulu
I got 186.04 g/mole... did i do that right?
Answered by
Lulu
never mind, thank you :)
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