Asked by Ana
What minimum number of moles of NH4Cl must be added to 1.0 liter of solution that is 0.10 M in Mg(NO3)2 and 1.0 M in NH3 to prevent precipitation of Mg(No3)2?
Answers
Answered by
DrBob222
Mg(OH)2 ==> Mg^+2 + 2OH^-
Ksp = (Mg^+2)(OH^-)^2
Kb for NH3 = (NH4^+)(OH^-)/(NH3)
Solve Ksp for OH^-. You now Mg so there is only one unknown. Substitute OH from that calculation into Kb for NH3. You know NH3 and Mg^+2, solve for NH4^+, then convert that molarity to grams NH4Cl. Post your work if you get stuck.
Ksp = (Mg^+2)(OH^-)^2
Kb for NH3 = (NH4^+)(OH^-)/(NH3)
Solve Ksp for OH^-. You now Mg so there is only one unknown. Substitute OH from that calculation into Kb for NH3. You know NH3 and Mg^+2, solve for NH4^+, then convert that molarity to grams NH4Cl. Post your work if you get stuck.
Answered by
coleman
how do you know Mg?
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