Asked by Lucas
Find the minimum number of terms in the geometric series 10 + 8 + 32/5 + ... such that the sum is greater than 49.
Answers
Answered by
Reiny
In this GP, a = 10, r = 4/5
remember that
S(n) = a(1 - r^n)/(1-r)
Just like in your last question, find n so they are equal, then bump it up to the next whole number.
remember that
S(n) = a(1 - r^n)/(1-r)
Just like in your last question, find n so they are equal, then bump it up to the next whole number.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.