Question

A daredevil leaves the end of a ramp with a speed of 32.0 m/s if his speed is 29.8 m/s when he reaches the peak of the path, what is the maximum height that he reaches?

how do i do thiss?

Answer 1

well,his horzontal speed is all he has at the peak, so vertical speed at launch is

vi^2=32^2-29.8^2
solve for Vi
Then for height,
Vi^2=2*g*h solve for height

Answer 2

vi=11.66

h=2.124