Question

A daredevil tries to launch out of a canon and land safely in a safety net. The canon is set at a launch angle of 49.0 degrees to the ground. The intial launch velocity is 27.3 meters/second. How far away should the safety net be placed from the cannon?

Answer 1

find the time it takes to have a final height of zero altitude.
with that time, how far horizontally does it travel?

Answer 2

answer it

Answer 3

u = 27.3 cos 49 forever
Vi = 27.3 sin 49 at start

v = Vi - gt
h = Vi t - (1/2)g t^2
at ground, h = 0
so
t = 2 Vi/g = Vi/4.9
now do it