Solve:(sec 35 degrees) (csc 55 degrees) - (tan 35 degrees) (cot 55 degrees)

Answer 1

I will skip the ° signs, so let's assume our numbers are degrees
also recall that because of complementary angles
sinA = cos(90-A)
tanA = cot(9-A)

so ...
(sec 35) (csc 55) - (tan 35) (cot55)
= 1/((cos35)(sin55)) - ((sin35)/cos35)) (cos55/sin55)
= 1/((sin55)(sin55)) - (cos55/sin55 ) (cos55/sin55)
= (1 - cos^2 55)/ sin^2 55
= sin^2 55/sin^2 55
= 1

Answer 2

Oh, ok thanks. I understand it now.

Answer 3

you are welcome