Asked by Anonymous

From the top of a tall building, a gun is fired. The bullet leaves the gun at a speed of 340 m/s, parallel to the ground. The bullet puts a hole in a window of another building and hits the wall that faces the window. (y = 0.42 m, and x = 7.2 m.)Determine the distances D and H, which locate the point where the gun was fired. Assume that the bullet does not slow down as it passes through the window.

Answers

Answered by rebika
let vy=is vertical componet then t' time of flight
x=ut'
y=vyt'-gt'^2/2
then eliminate the two equation
H= y +gt^2/2
and to find vy
vy=yu/x +gx/2u
D+x=ut
substitute the tow equation,
D=usqrt(2H)/g -x
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