Asked by Anonymous
An elevator in a tall building is allowed to reach a maximum speed of 3.0 m/s going down. What must the tension be in the cable to stop this elevator over a distance of 2.4 m if the elevator has a mass of 1500 kg including occupants? Need step by step help please!
Answers
Answered by
bobpursley
find the accelearation:
Vf^2=Vi^2+2ad
a= -1/2 Vi^2/d= in my head....-4.5/2.4
tension= mass(g+4.5/2.4)
Vf^2=Vi^2+2ad
a= -1/2 Vi^2/d= in my head....-4.5/2.4
tension= mass(g+4.5/2.4)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.