Asked by Anonymous

A lead fishing weight with a mass of 57 g absorbs 146 cal of heat.If its initial temperature is 48^C, what is its final temperature?
Answered by TutorCat
Q=mc∆t
Q = heat energy
m = mass
c = specific heat (of lead) [you need to look this number up]
∆t= change in temperature (= final - initial temp)

Answered by l
57
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