Asked by niks

What weight of lead nitrate in grams would need to be dissolved in 400 mL of water to prepare a 270 ppm solution of Pb2+?
Answered by DrBob222
1 ppm = 1 mg/L
270 ppm = 270 mg/L
Convert that to mg/400 mL.
270 x (400/1000) = ? mg in 400 mL
Change to grams.
Answered by 2020
0.108
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