Asked by Keli
Lead ii nitrate was added to a small test tube as well as Sodium hydroxide. What is the equilibrium equation for the reaction of lead ii ions and hydroxide ions?
Answers
Answered by
DrBob222
The small ii s should be II.
and in parentheses as (II).
Pb^+2 + 2OH^- ==> Pb(OH)2(s).
If excess OH^- is added, the Pb(OH)2(s) dissolves to form a complex ion.
Pb(OH)2(s) + 2OH^- ==> Pb(OH)<sub>4</sub><sup>-2</sup>
and in parentheses as (II).
Pb^+2 + 2OH^- ==> Pb(OH)2(s).
If excess OH^- is added, the Pb(OH)2(s) dissolves to form a complex ion.
Pb(OH)2(s) + 2OH^- ==> Pb(OH)<sub>4</sub><sup>-2</sup>