Asked by unknown
I find from the first equation that x = 3y and plugging in to the second equation we get
o.2y+37(-3y)=23
0.2y-111y=23
-110.8y=23
y=-23/110.8
x=69/110.8
need help to understand why the elimination process in not work in this linear equation?
o.2y+37(-3y)=23
0.2y-111y=23
-110.8y=23
y=-23/110.8
x=69/110.8
need help to understand why the elimination process in not work in this linear equation?
Answers
Answered by
bobpursley
without both equations, I do not have a clue either.
Answered by
unknown
12y +4x=0
0.2y+37x=23
does this help
0.2y+37x=23
does this help
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