What is the equation to find the dimensions of a rectangular garden with a perimeter of 54 feet and a length that is 3 feet shorter than twice its width?

1 answer

To find the dimensions of the rectangular garden, we can set up equations based on the information provided.

Let the width of the garden be \( w \) feet. According to the problem, the length \( l \) is 3 feet shorter than twice the width. This relationship can be expressed as:

\[ l = 2w - 3 \]

We are also given that the perimeter \( P \) of the rectangle is 54 feet. The formula for the perimeter of a rectangle is given by:

\[ P = 2l + 2w \]

Substituting the given perimeter into the equation, we have:

\[ 2l + 2w = 54 \]

We can simplify this equation by dividing all terms by 2:

\[ l + w = 27 \]

Now we have a system of two equations:

  1. \( l = 2w - 3 \)
  2. \( l + w = 27 \)

Next, we can substitute the expression for \( l \) from the first equation into the second equation:

\[ (2w - 3) + w = 27 \]

Combining like terms gives:

\[ 3w - 3 = 27 \]

Now add 3 to both sides:

\[ 3w = 30 \]

Dividing both sides by 3 yields:

\[ w = 10 \]

Now that we have the width, we can find the length using the first equation:

\[ l = 2w - 3 = 2(10) - 3 = 20 - 3 = 17 \]

Thus, the dimensions of the rectangular garden are:

  • Width \( w = 10 \) feet
  • Length \( l = 17 \) feet

In conclusion, the dimensions of the garden are:

  • Width: 10 feet
  • Length: 17 feet