Question

The density of a 1.0 M solution of NaCl is 1.04 g/mol and its specific heat, c, is 3.60 J/C*g. How much heat is absorbed by 31.4 mL of this solution if the temperature rises from 18.6 C to 29.7 C?

Answer 1

Use the density to convert 31.4 mL of the solution to mass. Then,
q = mass x specific heat x (Tfinal-Tinitial).

Answer 2

is it 0.6527 J?

Answer 3

I got 1310J