Question

Once I have the molarity for KHP which is 0.0027 M, and i add 14.48 mL of NaOH to the solution, what is the concentration of NaOH in the solution.

Answer 1

I wonder if you REALLY have the molarity of KHP. Usually that is a solid and one weighs it as a solid and titrates the entire sample; thus, moles is the number we needed. However, if you mean what you say, then mL x M = mL x M.
Since you don't list a volume for KHP, I suspect 0.0027 is moles, then, since NaOH and KHP react 1:1, we know moles NaOH = 0.0027, also, and
M NaOH = 0.0027/0.1448 = ??

Answer 2

Did i get it wrong? It has KHP molar mass at 204.33 g/mol and we use 0.556 g of KHP dissolved in water. THen if 14.48 mL of NaOH is used to reach endpoint, it needs the concentration of NaOH?

Answer 3

No, you did it right but you labeled it wrong.
moles KHP = 0.556 g KHP/204.33 = 0./00272 ( I wouldn't throw away the last 2).
Then since 1 mole KHP = 1 mole NaOH, then
M NaOH = moles NaOH/L NaOH = 0.00272/0.01448 = 0.1879 which to three significant figures rounds to 0.188 M.
Your only error was labeling 0.0027 as M KHP and not as moles KHP.

Answer 4

thank you for your help!!