Question

A solution of vinegar is 5.16% by mass aetic acid, CH3CO2H, in water. Assuming the density of vinegar is 1.00 g/mL, what is the molarity of the acetic acid?
5.16% CH3COOH by mass means 5.16 g CH3COOH in 100 grams of solution. That is 5.16 g CH3COOH/100 g soln.
moles CH3COOH = 5.16/molar mass CH3COOH = ??
g soln = 100 g. Density of 1.00 g/mL means the 100 g has a volume of 100 mL or 0.10 L.
So M = moles from above/0.1 L = ??

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