Asked by Megan
A 26.5 g sample of ethylene glycol, a car radiator coolant, loses 675 J of heat. What was the initial temperature of ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/gK)?
Please help me, I don't even know where to begin!!
Please help me, I don't even know where to begin!!
Answers
Answered by
DrBob222
q = mass e.g. x specific heat e.g. x (Tfinal-Tinitial).
Since the coolant LOST (released) 67 J, be sure to set q = -675
Since the coolant LOST (released) 67 J, be sure to set q = -675
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