Asked by boop
If you could drill a hole through the Earth and drop an object into the hole, how would Earth's gravity affect the object and why?(1 point)
Responses
The object would fall out the other side.
The object would fall out the other side.
The object would fall down from one side of the hole to the edge of the other side, and then fall back down to the start. This pattern would continue forever.
The object would fall down from one side of the hole to the edge of the other side, and then fall back down to the start. This pattern would continue forever.
The object will not fall into the hole because the object would be falling "up" to a viewer on the other side.
The object will not fall into the hole because the object would be falling "up" to a viewer on the other side.
The object would become stationary at the center of the Earth.
Responses
The object would fall out the other side.
The object would fall out the other side.
The object would fall down from one side of the hole to the edge of the other side, and then fall back down to the start. This pattern would continue forever.
The object would fall down from one side of the hole to the edge of the other side, and then fall back down to the start. This pattern would continue forever.
The object will not fall into the hole because the object would be falling "up" to a viewer on the other side.
The object will not fall into the hole because the object would be falling "up" to a viewer on the other side.
The object would become stationary at the center of the Earth.
Answers
Answered by
boop
the object would fall out the other side.
Answered by
GPT-5 mini
The object would fall down from one side of the hole to the edge of the other side, pass through, and then fall back — repeating forever (ignoring air resistance and friction).
Why: inside the Earth gravity always pulls toward the center and the net force on the object is proportional to its distance r from the center (only the mass enclosed within radius r contributes). That gives a restoring force F ∝ −r, so the motion is simple harmonic: it passes through the center and reaches the same height on the other side. (With air resistance or friction it would lose energy and eventually come to rest at the center.)
Why: inside the Earth gravity always pulls toward the center and the net force on the object is proportional to its distance r from the center (only the mass enclosed within radius r contributes). That gives a restoring force F ∝ −r, so the motion is simple harmonic: it passes through the center and reaches the same height on the other side. (With air resistance or friction it would lose energy and eventually come to rest at the center.)
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