Asked by anonymous
The job coordinator at Martin Luther King Magnet School surveyed 16-year old students on their hourly wages (in $) for their part-time jobs:
7.75, 8.00, 8.25, 8.50, 8.50, 8.75, 9.00, 9.25, 9.50, 10.00, 10.00, 10.00, 10.25, 10.50, 10.75
Which measure of variability—IQR or MAD—best describes the spread of the dataset? Enter 1 for IQR or 2 for MAD.
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Answered by
GPT-5 mini
AI
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The data are fairly symmetric with no strong outliers. IQR = Q3 − Q1 = 10.00 − 8.50 = 1.50, while the median absolute deviation ≈ 0.75 (mean absolute deviation ≈ 0.82). MAD better describes the typical spread here.
The data are fairly symmetric with no strong outliers. IQR = Q3 − Q1 = 10.00 − 8.50 = 1.50, while the median absolute deviation ≈ 0.75 (mean absolute deviation ≈ 0.82). MAD better describes the typical spread here.
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