Question

Four circles, each with a radius of 2 inches, are removed from a square.
Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square?

(16 – 4π) in.2
(16 – π) in.2
(64 – 16π) in.2
(64 – 4π) in.2

Answer 1

Each circle has area πr^2 = π(2^2) = 4π. Four circles remove 4·4π = 16π.

The square must have side 2·(2+2) = 8 (two diameters across), so its area is 8^2 = 64.

Remaining area = 64 − 16π.