show the opposite: the value is <1
3x^2-6x+5<1
3x^2-6x+4<0
x= (6+-sqrt(36-48))/6
well the serd here is imaginary. So the assumption of being less than one is false.
What does it mean by:
Show that the "value of 3x^2-6x+5" cannot be less than 1. ?
1 answer